Originally Posted by secbro17
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i have calculus next BWAHAHAHAHAHAHAHA
we just started Integration also called Anti Derivatives. <3 calculus
f(x)= 3x^2+4
f'(x)=(3(x+h)^2+4-3x^2-4)/(h)
f'(x)=(3x^2+3h^2+6hx+4-3x^2-4)/(h)
f'(x)=(3h^2+6hx)/h
f'(x)=3h+6x
f'(x)=3(0)+6x
f'(x)=6x
Same problem just posting it again because it rules all. Dervative of 3x^2+4 is 6x
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D:
Or... we could just cut that whole equation down by 1239120893 steps:
f(x)=3x^2+4
f'(x)=3x*2^(2-1)+4*0^-1
f'(x)=6x