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Old 07-25-2008, 06:53 AM   #1
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Math People: Help!

*Generate all combinations of 6 numbers from a pool of 1 to 10, 11 to 20, 21 to 30, 31 to 40, and 51 to 60,
*In each combination no numbers can repeat
*In each combination, a maximum of 1 number can be used from each pool, with the exception of one pool where you may use 2 numbers.

How many combination will there be?
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Old 07-26-2008, 10:22 PM   #2
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Wahahaha, I should've seen this sooner...

Let's see...

If you only have one pool in which you may draw two numbers from, but there are five pools, that means there is a multiplication factor of 5.

Each number in that set can only be paired with a number of the set minus that number in that set. Therefore, (9+8+7+6...+1).

Each successive set is 10. There are four remaining pools to draw from, so that is 10^4.

Therefore, you have...

(9+1)9/2 = 45

10^4 = 10,000

5(45)(10,000) = 2,250,000

Your total number of possible combinations is 2,250,000.
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Old 07-26-2008, 10:24 PM   #3
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/burnsthisthread
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Old 07-26-2008, 10:26 PM   #4
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Triumph soo smart +rep
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Old 07-26-2008, 10:28 PM   #5
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Originally Posted by A_Forever View Post
/burnsthisthread
Math needs love too!
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Old 07-26-2008, 10:31 PM   #6
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Originally Posted by Triumph View Post
Math needs love too!
Math ftw.

Statistics just bore me... /would rather do Alg/Trig/Geo
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Old 07-26-2008, 10:48 PM   #7
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Originally Posted by Triumph View Post
Math needs love too!
NO
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Old 07-26-2008, 10:50 PM   #8
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im taking AP calc next year triumph better do my homework for me
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Old 07-26-2008, 11:00 PM   #9
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I only got a 4 on the BC test, I was not happy.
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Old 07-26-2008, 11:26 PM   #10
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Originally Posted by Triumph View Post
I only got a 4 on the BC test, I was not happy.
A 4?!

I feel your pain.
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