Physics is the bane of my existence

Uklyvian · 10-17-2009, 01:01 AM

Hey guys I can't figure out this problem for the life of me....

A 3.50 kg object is attached to a vertical rod by two strings as in the figure below. The object rotates in a horizontal circle at constant speed 4.95 m/s.

What is the tension on the lower and upper string D:?

**Hessah** · 10-17-2009, 01:13 AM

You come to us when you have a school problem.. hmph!

Uklyvian · 10-17-2009, 01:16 AM

O.o would you like to me to come to you other times too o.O? I quietly help out around here .-. /gives lots of money when asked for FF events D;

**Hessah** · 10-17-2009, 01:17 AM

Aw ok I'm sorry.. I'll take that back.. kekeke

Uklyvian · 10-17-2009, 01:18 AM

lol....no one in my class can get it either D; i think this problem is cursed

**Hessah** · 10-17-2009, 01:20 AM

Do you have a formula for tension? That's the formula for force right?

**Ralath** · 10-17-2009, 01:22 AM

I wonder if Lam knows. Kekeke. He just posted a super long thing on Physics. If I see him online, I'll have him look at this.

/has never taken a Physics class in my life

Uklyvian · 10-17-2009, 01:22 AM

F=MA...tension is essentially force.

It should be like this I think

cos θ = 1.5/ 2
= 41.41 degrees
T1y = mg
T1 sin θ = mg
T1 sin 41.41 = 3.5(9.8)
T1 = 51.85N

but it doesn't work D;

**a.L** · 10-17-2009, 01:54 AM

T1 = 49.28 N?

Bleh.

lamchopz · 10-17-2009, 02:04 AM

Try centripetal motion equation.