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Instructions to complete. Highlight to see. Solution is based on given point.
Warning: HUGE post.
1. It can be seen in the top three boxes that in the upper-right box, a 9 cannot be on the bottom two rows of that box. Therefore, 9 is in the top right-hand corner.
2. In the same box, it can be concluded that 6, 7, and 8 are the numbers required to complete it. In the top row, however, 6 and 7 are already present. This leaves 8.
3. Observe the middle box. The box lacks a 1, 4, 5, 6, 8, and 9. However, it can be seen that 4, 5, 6, 8, and 9 cannot fit in the middle box of the first row. Thus, 1.
4. In the same box, but on the bottom row, it can be observed that 4, 5, 6, and 9 are not applicable to that box, but 8 is.
5. In the fifth column, the number 5 can be filled because it is the only missing number in the column.
6. In the top left box, it can be observed that only 5 can only fit in the top right hand corner of that box. This allows 1 to be filled in the remaining box.
7. In the second column from the top overall, it can be seen that 6, 7, and 8 are lacking. However, 6 and 7 are in the middle box of the top row, so 8 can be filled in the one remaining box in the second row and second box.
8. This one is tough to explain. If you observe the bottom right box, you'll notice how 1 is confined to the seventh column from the left. Keeping that knowledge in mind, look up one box. It can be seen that 1 can only be in the middle box of that box.
9. Look at the box just under the top right box. It can be observed that 1 can only be in the middle box of the bottom row of that box. 9 can also be filled on top of that in the middle box of the middle row, since it completes the second column.
10. Observe the middle box. It can be seen that 9 can only be in the top left hand box of the middle box.
11. Look at the third box from the left in the second row. It can be observed that 9 can only be in the bottom left-hand box of that box.
12. Once again, observe the middle box. In the second row, first box, it can be deduced that 6 is the only integer that can fit in that box.
13. With this knowledge, look to the right box of the second row. It can be seen that 5 can only fit there, and 4 below it.
14. Look at the fourth column from the left. It can be seen that 1 and 4 are the only ones needed; however, it can also be seen that 4 cannot fit in the bottom box. Thus, 4 is on the top box and 1 is on the bottom box of the column. This also fills in 1 in the top row of the middle box of the top row.
15. In the bottom row of the bottom row of boxes, it can be seen that 2, 6, and 8 are the numbers needed. However, when looking at the bottom right box, it can be concluded that only 6 can go there.
16. Observe the bottom right box. It can be concluded that 1 can only be in the first box of the second row.
17. Observe the second row of the bottom row of boxes. It can be seen that 6, 7, and 8 are required. However, it can be deduced that 7 can only be in the bottom right box.
18. In the bottom right box of the bottom row, it can be seen 4 and 8 are required. Ergo, it can be seen that 8 can clearly not fit in the first box in the first row, thus 4 goes there and 8 goes in the remaining box. In the 7th column, 7 can also be placed to finish the column.
19. In the right box in the second row, it can be seen that 2, 3, 4, and 6 are required. However, in the second box in the first row, only 6 can fit. With this knowledge, it can be easily seen that 7 goes in the remaining box in the eighth row, and a 6 right next to it, completing the top right box.
20. In the left box in the second row, it can be seen that the far right box in the first row can only be a 2.
21. In the bottom left box, it can be seen that the only number that can go in the far right box in the first row is a 6. A 7 can also be placed above this number in the bottom right box of the third row of the left box of the middle row to complete the third column. The far right box of the first row of the middle box of the third row of boxes can also be filled with a 2 to complete the 7th row.
22. In the middle box of the third row of boxes, it can be seen that only an 8 can go in the bottom right box of the third row. Consequently, a 6 can go above it to finish the box.
23. I'm getting a bit tired, so I'll cut it short: Now, the bottom left box of the third row of boxes can be completed. Self-explanatory.
24. It can be seen in the left box of the second row in the first row that a 4 and 5 is required. However, the 4 in the first column cancels the 4 chance. Consequently, finish the row with putting a 5 in the first box of the fourth row and a 4 in the last box of the same row.
25. It can be seen in the left box of the middle row of the left box of the middle row of boxes that a 3 can only go there. Complete the row by finishing the last box in the same row with a 2.
26. I'm not sure why I'm writing this step, since there's two boxes left. Fill the box on the left with a 6, and the box on the right with a 3.
Congratulations, you are done. Total elapsed time: 01:04:26.
Last edited by Triumph; 09-10-2008 at 09:19 PM..
Reason: Step 3, missing step.
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