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Old 01-30-2008, 02:27 PM   #7
secbro20
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i have calculus next BWAHAHAHAHAHAHAHA

we just started Integration also called Anti Derivatives. <3 calculus

f(x)= 3x^2+4

f'(x)=(3(x+h)^2+4-3x^2-4)/(h)

f'(x)=(3x^2+3h^2+6hx+4-3x^2-4)/(h)

f'(x)=(3h^2+6hx)/h

f'(x)=3h+6x

f'(x)=3(0)+6x

f'(x)=6x

Same problem just posting it again because it rules all. Dervative of 3x^2+4 is 6x
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