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**secbro20** · 01-30-2008, 12:59 PM

f(x)= 3x^2+4

f'(x)=(3(x+h)^2+4-3x^2-4)/(h)

f'(x)=(3x^2+3h^2+6hx+4-3x^2-4)/(h)

f'(x)=(3h^2+6hx)/h

f'(x)=3h+6x

f'(x)=3(0)+6x

f'(x)=6x

01-30-2008, 12:59 PM	#3
secbro20 Currently Gameless Posts: 1,492	f(x)= 3x^2+4 f'(x)=(3(x+h)^2+4-3x^2-4)/(h) f'(x)=(3x^2+3h^2+6hx+4-3x^2-4)/(h) f'(x)=(3h^2+6hx)/h f'(x)=3h+6x f'(x)=3(0)+6x f'(x)=6x __________________ World of Warcraft Realm-Arathor 80-Night Elf Priest-Nezarn ->Check my Progress<- *Once a G____G, always a G____G*