Originally Posted by Lirange
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Your asian, you should have a calculator brain.
I'll just ask my teacher in class tomorrow-_-.
There's this one problem and I got to
ax=bx-ab+3a-8
Would I divide by a and have everything on the right side be over a? Then how would i get the x from bx to the left side.
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You just move everything with x to one side and anything without to the other.
Then you can group the x and solve.
ax - bx = -ab + 3a -8
(a-b) x = (3-b) a - 8
x = ((3-b) a - 8)/(a-b)
done