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**Hessah** · 04-27-2010, 04:32 AM

you can see that you've got 2x (NO3) on the right..

so you'll need to make two lots of NO3 on the left..

Ca(OH)2 + 2HNO3 → CA(NO3)2 + H2O

now you have 4x H on the left (Ca(OH)2 + 2HNO3)

So you need 4H on the other side..

Ca(OH)2 + 2HNO3 → CA(NO3)2 + 2H2O

everything else now balances..

I'm not sure if that's the correct way to explain it though...

04-27-2010, 04:32 AM	#2
Hessah Hardcore Procrastinator Burger Time Champion! Cannon Ball Follies 2 Champion! Tournaments Won: 51 In-Game Name: Hessah / Ble~ehs Current Level: 91 / 85 / 79 / 65 / 28 Server: Teeeeeee-vah Posts: 9,581	you can see that you've got 2x (NO3) on the right.. so you'll need to make two lots of NO3 on the left.. Ca(OH)2 + 2HNO3 → CA(NO3)2 + H2O now you have 4x H on the left (Ca(OH)2 + 2HNO3) So you need 4H on the other side.. Ca(OH)2 + 2HNO3 → CA(NO3)2 + 2H2O everything else now balances.. I'm not sure if that's the correct way to explain it though... __________________ G____G G____GTevaG____G Heart___G_Hessah_G___Heart 79 - Paladin \| 85 - Enchanter \| 91 - Scoutxx Ninja text! For those who's easily amused I can show you the woooorld! I don't want to see it! okay...