View Single Post
Old 07-26-2008, 10:22 PM   #2
Triumph
Wiki Head Admin


 
Triumph's Avatar
 
Deal or No Deal Champion!Tournaments Won: 1

In-Game Name: FFXIV
Current Level: 80
Server: Coeurl
Posts: 2,323
Triumph has much to be proud ofTriumph has much to be proud ofTriumph has much to be proud ofTriumph has much to be proud ofTriumph has much to be proud ofTriumph has much to be proud ofTriumph has much to be proud ofTriumph has much to be proud ofTriumph has much to be proud of
Wahahaha, I should've seen this sooner...

Let's see...

If you only have one pool in which you may draw two numbers from, but there are five pools, that means there is a multiplication factor of 5.

Each number in that set can only be paired with a number of the set minus that number in that set. Therefore, (9+8+7+6...+1).

Each successive set is 10. There are four remaining pools to draw from, so that is 10^4.

Therefore, you have...

(9+1)9/2 = 45

10^4 = 10,000

5(45)(10,000) = 2,250,000

Your total number of possible combinations is 2,250,000.
Triumph is offline   Reply With Quote