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Math People: Help!
*Generate all combinations of 6 numbers from a pool of 1 to 10, 11 to 20, 21 to 30, 31 to 40, and 51 to 60,
*In each combination no numbers can repeat *In each combination, a maximum of 1 number can be used from each pool, with the exception of one pool where you may use 2 numbers. How many combination will there be? |
Wahahaha, I should've seen this sooner...
Let's see... If you only have one pool in which you may draw two numbers from, but there are five pools, that means there is a multiplication factor of 5. Each number in that set can only be paired with a number of the set minus that number in that set. Therefore, (9+8+7+6...+1). Each successive set is 10. There are four remaining pools to draw from, so that is 10^4. Therefore, you have... (9+1)9/2 = 45 10^4 = 10,000 5(45)(10,000) = 2,250,000 Your total number of possible combinations is 2,250,000. |
/burnsthisthread
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Triumph soo smart :cutielove: +rep
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Statistics just bore me... /would rather do Alg/Trig/Geo |
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im taking AP calc next year triumph better do my homework for me :cutielove:
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I only got a 4 on the BC test, I was not happy.
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I feel your pain. :cries: |
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