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ThievingSix 07-25-2008 06:53 AM

Math People: Help!
 
*Generate all combinations of 6 numbers from a pool of 1 to 10, 11 to 20, 21 to 30, 31 to 40, and 51 to 60,
*In each combination no numbers can repeat
*In each combination, a maximum of 1 number can be used from each pool, with the exception of one pool where you may use 2 numbers.

How many combination will there be?

Triumph 07-26-2008 10:22 PM

Wahahaha, I should've seen this sooner...

Let's see...

If you only have one pool in which you may draw two numbers from, but there are five pools, that means there is a multiplication factor of 5.

Each number in that set can only be paired with a number of the set minus that number in that set. Therefore, (9+8+7+6...+1).

Each successive set is 10. There are four remaining pools to draw from, so that is 10^4.

Therefore, you have...

(9+1)9/2 = 45

10^4 = 10,000

5(45)(10,000) = 2,250,000

Your total number of possible combinations is 2,250,000.

A_Forever 07-26-2008 10:24 PM

/burnsthisthread

Dojima 07-26-2008 10:26 PM

Triumph soo smart :cutielove: +rep

Triumph 07-26-2008 10:28 PM

Quote:

Originally Posted by A_Forever (Post 198853)
/burnsthisthread

Math needs love too! :cutielove:

Hyper 07-26-2008 10:31 PM

Quote:

Originally Posted by Triumph (Post 198856)
Math needs love too! :cutielove:

Math ftw. :cutielove:

Statistics just bore me... /would rather do Alg/Trig/Geo

Rightclaw 07-26-2008 10:48 PM

Quote:

Originally Posted by Triumph (Post 198856)
Math needs love too! :cutielove:

NO

Dojima 07-26-2008 10:50 PM

im taking AP calc next year triumph better do my homework for me :cutielove:

Triumph 07-26-2008 11:00 PM

I only got a 4 on the BC test, I was not happy.

Hyper 07-26-2008 11:26 PM

Quote:

Originally Posted by Triumph (Post 198877)
I only got a 4 on the BC test, I was not happy.

A 4?!

I feel your pain. :cries:


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