Fiesta Fan Forums - Class is now in session!!!

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- - Class is now in session!!! (http://www.fiestafan.com/forums/showthread.php?t=11173)

Sinus_infection

07-21-2008 09:41 PM

Quote:

Originally Posted by Maki (Post 193826)

Eww! This reminds me of school.
T_T: End of the school holidays as of yesterday~
Starting school in 1 hour and 45 minutes *sniffles*

I HAVE A QUESTION!

A 500mL bottle of concentrated sulfuric acid (18molL-1) was dropped in a laboratory accident. Solid sodium hydrogen carbonate (NaHCO3) was used to neutralize the spilled acid.

a) Justify the choice of the solid sodium hydrogen carbonate to clean up the spill. Include relavent equaltions(s).

b) Calculate the minimum mass of sodium hydrogen carbonate needed to neutralise the spilled acid completely.

Good luck guys!

(HINT: question a is worth 4 marks and question b is worth 3.)

theoratically...mathematically....scientifically speaking......:zzz::nahnah:the whats a what goes to the doohicky and the coombuster thing soes 3 times and the final answer is*drum roll plz*!!!!!!!!:zzz::zzz::zzz:

Maki	07-22-2008 04:12 AM

*drum rolls*...?

Ralath

07-22-2008 05:19 AM

for...?

I solved the problem for you already (I think).... Dx

lamchopz

07-22-2008 02:51 PM

Quote:

Originally Posted by Ralath (Post 193887)

eccchhhhhhh!!! Is this AP Chem? Dx

Here's what I did.

:3?

Brings me back to high school chemistry. :smarty:

I think Ralath got the products. I disagree slightly on the balanced equation:

H2SO4 (l) + 2NaHCO3 (s) -> Na2SO4 + 2H2O + 2CO2

(remember to reduce the coefficients to the simplest ratio)

Why can't we have a maths lesson? It's easier. :laugh:

Hyper

07-22-2008 03:15 PM

Quote:

Originally Posted by lamchopz (Post 194781)

H2SO4 (l) + 2NaHCO3 (s) -> Na2SO4 + 2H2O + 2CO2

(remember to reduce the coefficients to the simplest ratio)

Owned. :smarty:

Ralath

07-22-2008 06:51 PM

Actually. I did see that.

But then I was having problems finding enough oxygens on both sides.

So... yeah. Dx

I was too excited to actually figure that out. Couldn't figure out what to do with the carbons for a long time...

So I just left it like it is.

But doesn't change part B.

lamchopz

07-23-2008 02:26 AM

The oxidation number of each element hasn't changed so I'm guessing you used trials and errors.

What I did was first balance the sodium, then the hydrogen and finally the oxygen (consequently the carbon).

Part b is easy once you get the balanced equation.

Ralath

07-23-2008 03:20 AM

hrm. I can't remember what I did... lol..

Oh no wait. I know. I stuck in the 9 in front after I figured out the 9 moles. And then I just forgot to reduce. xD

Hessah

07-23-2008 03:32 AM

-throws a paper plane-

This room is full of chemistry nerds!!!!!

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