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kirbysprite 07-21-2008 09:13 PM

Quote:

Originally Posted by Maki (Post 193826)
Eww! This reminds me of school.
T_T: End of the school holidays as of yesterday~
Starting school in 1 hour and 45 minutes *sniffles*

I HAVE A QUESTION!

A 500mL bottle of concentrated sulfuric acid (18molL-1) was dropped in a laboratory accident. Solid sodium hydrogen carbonate (NaHCO3) was used to neutralize the spilled acid.

a) Justify the choice of the solid sodium hydrogen carbonate to clean up the spill. Include relavent equaltions(s).

b) Calculate the minimum mass of sodium hydrogen carbonate needed to neutralise the spilled acid completely.



Good luck guys!

(HINT: question a is worth 4 marks and question b is worth 3.)

This isn't science it's math. Get that out of your system...

Hyper 07-21-2008 09:16 PM

Quote:

Originally Posted by Spirit (Post 193760)

LMAO.

Quote:

Originally Posted by A_Forever (Post 193761)

LOOOOOOOOOOOOL. QFT.

Maki 07-21-2008 09:21 PM

Quote:

Originally Posted by kirbysprite (Post 193853)
This isn't science it's math. Get that out of your system...

:hulksmash: it got maths in it!
Like.. balancing the equations you need to know your 1,2 and 3s!

A_Forever 07-21-2008 09:22 PM

Math and science go hand-in-hand.

kirbysprite 07-21-2008 09:23 PM

Yeah they do...

PoisoN 07-21-2008 09:34 PM

Quote:

Originally Posted by A_Forever (Post 193871)
Math and science go hand-in-hand.

depends wut science Biology usualy duznt deal with math

Ralath 07-21-2008 09:36 PM

eccchhhhhhh!!! Is this AP Chem? Dx

Here's what I did.

Quote:

Originally Posted by Maki (Post 193826)

A 500mL bottle of concentrated sulfuric acid (18molL-1) was dropped in a laboratory accident. Solid sodium hydrogen carbonate (NaHCO3) was used to neutralize the spilled acid.

a) Justify the choice of the solid sodium hydrogen carbonate to clean up the spill. Include relevant equations(s).

H2SO4+NaHCO3=CO2+H2O+NaSO4

500ml of H2SO4 (sulfuric acid) with 18molL-1 is 9 mols.

Balancing the rest of the equation gives you:

9(H2SO4)+18(NaHCO3)=18(CO2)+9(H2O)+9(Na2SO4)

Your products are then CO2 (harmless), H2O (even more harmless), and Na2SO4 (a precipitate).



b) Calculate the minimum mass of sodium hydrogen carbonate needed to neutralise the spilled acid completely.


http://img.photobucket.com/albums/v30/Ralath/chem.jpg


:3?

kirbysprite 07-21-2008 09:38 PM

Oh balancing equations? I hated that...

PoisoN 07-21-2008 09:38 PM

balancing equations isnt hard :zzz:

kirbysprite 07-21-2008 09:40 PM

Quote:

Originally Posted by PoisoN (Post 193894)
balancing equations isnt hard :zzz:

For me it was...

I used something called the EBA or something... I hate trial and error...


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